Appian ACD201최신업데이트버전덤프문제 & ACD201퍼펙트공부문제
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참고: Pass4Test에서 Google Drive로 공유하는 무료, 최신 ACD201 시험 문제집이 있습니다: https://drive.google.com/open?id=19Em0a-vZgxsfZU_reyoDHXmL7zFYhaYq
여러분이 다른 사이트에서도Appian인증ACD201시험 관련덤프자료를 보셨을 것입니다 하지만 우리Pass4Test의 자료만의 최고의 전문가들이 만들어낸 제일 전면적이고 또 최신 업데이트일 것입니다.우리덤프의 문제와 답으로 여러분은 꼭 한번에Appian인증ACD201시험을 패스하실 수 있습니다.
Appian ACD201 시험요강:
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>> Appian ACD201최신 업데이트버전 덤프문제 <<
100% 합격보장 가능한 ACD201최신 업데이트버전 덤프문제 덤프
Appian인증ACD201시험의자격증은 여러분에 많은 도움이 되리라 믿습니다. 하시는 일에서 한층 더 업그레이드될 것이고 생활에서도 분명히 많은 도움이 될 것입니다. 자격증취득 즉 재산을 얻었죠.Appian인증ACD201시험은 여러분이 it지식테스트시험입니다. Pass4Test에서는 여러분의 편리를 위하여 Pass4Test만의 최고의 최신의Appian ACD201덤프를 추천합니다. Pass4Test를 선택은 여러분이 최고의 선택입니다. Pass4Test는 제일 전면적인Appian ACD201인증시험자료의 문제와 답을 가지고 잇습니다.
최신 Senior Developer ACD201 무료샘플문제 (Q103-Q108):
질문 # 103
Which two options are correct regarding record relationships when using synced records in your application? (Choose two.)
- A. Many-to-one relationships can be established using record relationships.
- B. Up to 20 relationships can be added on a record type with data sync enabled.
- C. Record type relationships enforce referential integrity.
- D. Relationships can be established between any record types that have sync enabled, regardless of the source.
정답:A,B
설명:
Many-to-one relationships can be established between record types using record relationships.
Up to 20 relationships can be added to a record type with data sync enabled, according to Appian platform limits.
질문 # 104
You're designing an expression rule that needs to retrieve employees from a database for a given department and display their full name concatenated with their role in a list for a dropdown field.
Which design approach should you recommend?
- A. Query the data with a filter applied to only return employees for the given department. Using a!forEach(), for each item in the list, return the employee name and role.
- B. Query the data to return all employees. Using a!forEach(), for each item in the list, if the employee belongs to the given department, return the employee name and role, otherwise, return a null value.
- C. Query the data to return all employees. Use wherecontains() to return the employees for the given department and use a!forEach() to return the employee name and role for each item in the list.
정답:A
설명:
Querying the data with a filter to return only employees for the given department is the most efficient approach. Then, using a!forEach() to concatenate and return the employee name and role meets the dropdown display requirement without unnecessary processing.
질문 # 105
You need to create a read-only grid that displays support case information. Data for the support cases is mapped to the "Case" record type with data sync enabled.
Within the record, there are fields named "createdDateTime" and "resolvedDateTime". These two fields store the timestamps for when a case is created and resolved, respectively.
The grid includes a column indicating the number of hours between when the case was created and when it was resolved. This column must be sortable within the grid.
How should you calculate the hour value that will display in the column?
- A. Within the grid column, utilize an Appian function to calculate the number of hours between when the case was created and when it was resolved.
- B. Create a custom record field that evaluates in real-time, and calculates the number of hours between when the case was created and when it was resolved.
- C. Create a custom record field that evaluates at sync-time, and calculates the number of hours between when the case was created and the current date and time.
정답:B
설명:
A custom record field that evaluates in real-time and calculates the hours between "createdDateTime" and "resolvedDateTime" ensures the calculated value is available as a sortable field within the read-only grid.
질문 # 106
The synced record Task has a self-referential relationship defined in the column parentTaskId. There is a many-to- one record relationship between the id and parentTaskId called parentTask.
For a given task ID, you need to return the task name and the parent task name.
What should you do?
- A. Use a!queryRecordType() filtered on the task id once to return the task name and parent task ID. Query the record again to return the parent task name.
- B. Use a!queryRecordType() With a filter on the task id, with fields specified to return recordType!Task.
name and recordType!Task.parentTask.name. - C. Create a sync-time custom record field on the Task record called parentName. Specify this field to return in the query field selection.
정답:B
설명:
A single a!queryRecordType() call filtered by the task's id and selecting both recordType!Task.name and recordType!Task.parentTask.name leverages the existing self-referential relationship, returning the task name and its parent's name in one efficient query without additional custom fields or extra queries.
질문 # 107
You need to create an expression rule that will be reused throughout your environment.
What are two reasons why you should include meaningful test cases when creating a new expression rule? (Choose two.)
- A. To improve the performance of the environment.
- B. To enhance the appearance of the code.
- C. To facilitate Test-Driven Development.
- D. To accelerate various types of testing, including: unit, regression, exploratory.
정답:C,D
설명:
Meaningful test cases accelerate different testing types by providing clear validation scenarios for the rule.
They support Test-Driven Development by enabling you to define expected outcomes before or during rule creation.
질문 # 108
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